A diver springs upward from a board that is three meters above the water. At the instant she contacts the water her speed is 9.10 m/s and her body makes an angle of 82.0° with respect to the horizontal surface of the water. Determine her initial velocity, both magnitude and direction.
________m/s (magnitude)
________° (direction)
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Verified answer
Make note that the initial velocity is the horizontal velocity. During her dive, the horizontal velocity or initial velocity is always the same. At the point where a diver lands on the water, she forms 82° with her speed 9.1 m/s [contact]. We can use cosine formula and determine the value of that velocity. Well..
v_0 = 9.1 m/s * cos(82°)
≈ 1.27 m/s
The direction should be 0° due horizontal.
Good luck!
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