A rock is thrown straight out from a cliff. The initial velocity is 28.3 m/s.It takes the rock 3.41 s to reach the ground at the bottom of the cliff.
a) How high is the cliff?
What is the distance of the rock from the base of the cliff when it first hits?
A rock is thrown straight out from a cliff. The initial velocity is 23.5 m/s. It lands 83.5 m from the base of the cliff.
a) How long does it take the rock to hit the ground at the base of the cliff?
How high is the cliff?
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Verified answer
a) Height = 1/2 (t^2 x g), = 56.98 metres.
b) (3.41 x 28.3) = 96.5 metres.
a) (83.5/23.5) = 3.55 secs.
b) Height = 1/2 (t^2 x g), = 61.75 metres.