I am trying to solve a math problem that involves dividing 34 by 204 and converting the result to a fraction. When I do that, I get: .1666666667, but I am not sure how to convert this into a fraction... can anybody help?
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34/204 is your fraction. You can simplify it if you want, but it's already a fraction. Both 34 and 204 have 34 as a factor, so this simplifies to 1/6.
If you wanted to start with 0.166666, then find the repeating bit. In this case it starts in the hundreds place and is a single digit (6).
So your decimal can be broken down into 0.1 + 0.0(6) repeating. Take the repeating part and put it over as many "9"s as there are digits in the repeating part. Here, that's just 1 digit.
6/9
Since it was in the hundredths place, multiply the denominator by 10.
6/90
1/10 + 6/90
9/90 + 6/90
15/90
1/6.
Hi! We know that the fraction 34/204 = 0.1666666666666666..., and now we want to convert this decimal back to a fraction. The procedure to do this relies on a little trick I'll show you below.
So, say we let the variable x = 0.16666666666.... Then, notice that I can write 100x = 16.66666666666...
Now, let's subtract these two values,
99x = 100x - x = 16.66666666666... - 0.16666666666... = 16.5
So, we have 99x = 16.5. If we divide by 99, we get x = 16.5 / 99 = 33 / 198 = 1/6 (198 / 33 = 6).
So, we can also write the decimal x = 0.16666666... as 1/6. This checks too, as our original fraction 34/204 also reduces to 1/6 (204/34 = 6).
Hope this helps, and please pick for best answer!
That fraction is actually 0.166666... (with 6's going on forever.
So if you call it n, we have:
n = 0.16666..
Multiply both sides by 100, you get:
100n = 16.6666...
Now you can subtract the first from the second, this cancels out the repeated 6's, so now you have an equation that you can solve:
99n = 16.6666... - 0.16666...
99n = 16.66 - 0.16
99n = 16.5
Now divide both sides by 99:
n = 16.5 / 99
Multiply both sides by 2 to get rid of the "half" decimal in the numerator:
n = 33/198
This reduces to: 1/6
So 34/204 = 0.16666... = 1/6
https://www.khanacademy.org/math/algebra/solving-l...