You could probably multiply the entire top equation by 3 and the entire bottom equation by 2. That way you could add the two equations and the y's would cancel each other out. Then, solve for x. Take you answer for x and plug it into one of the equations to solve for y.
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3[0.3x – 0.2y = 4]
2[0.2x + 0.3y = -37/17]
0.9x-0.6y=12
0.4x+0.6y=-74/17
1.3x=130/17
x=100/17
0.3(100/17)–0.2y=4
30/17-0.2y=4
-0.2y=38/17
y=190/17
You isolate either the x or the y. In this case, I would cancel out the Ys. Multiply the top by 3, the bottom by 2, to get...
0.9x – 0.6y = 12
0.4x + 0.6y = 2(-37/17)
=> 1.3x = 12 + 2(-37/17)
You could probably multiply the entire top equation by 3 and the entire bottom equation by 2. That way you could add the two equations and the y's would cancel each other out. Then, solve for x. Take you answer for x and plug it into one of the equations to solve for y.
multiply the first equation by 3 and the second one by 2
when you add the new equations, the "y"s will be eliminated