I have tried to solve this, but can't get the right answer.
Suppose that a nuclear accident occurs and releases 60 grams of Strontium-90 into the atmosphere. How long will it take for Strontium-90 to decay to a level of 10 grams?
Just in case, K = -0.025 and the answer is 72.2 years.
Update:Thanks a lot!
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Verified answer
At t=0, there are 60 grams, so
10 = 60e^(-0.025t)
Taking natural logarithms on both sides gives
ln(10) = ln(60) - 0.025t
Solving for t gives
t = [ln(10) - ln(60)] / -0.025 = 71.67 years
a million. in basic terms plug in sixteen because of the fact the lead consistent(they did that already) and t=5715 remedy for A=8.01g 2. sixteen grams with a 0.5 existence of 10 s, capacity a million/2 of the sixteen grams would be long previous in 10s, 8g stay, after 20 secs, 4g stay (a million/2 of 8) 3. sixteen grams, same as 2. 8g after 25,000, 4g after 50,000