For your case, you'll only need to change the base on the first part of the equation. I'll use base 10 as it's built-in to a calculator and fairly easy to understand.
To change bases (from a to b), you use the following formula:
log(base a)x = log(base b)x / log(base b)a.
So for your specific example, you have:
log(base 3)24 = log(base 10)24 / log(base 10)3
= 1.3802 / 0.4771
= 2.8929
For the second part, you don't need to change the base as:
Rewrite as: Logb x^5 - Logb y^(1/4)+ Logb z^2 Use the rules to get: Logb (x^5/y^(1/4))*z^2) The addition signs correspond to multiplying and the subtraction signs correspond to division. You can check your answers on a calculator by substituting numbers such as x=3, y=5, and 7=z and 10 for b (you can use the LOG key on your calculator) or use (exponential) e and the LN key. You should get the same answers for both the original and simplified equation.
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I am sure this will help!! :-)
Hi,
For your case, you'll only need to change the base on the first part of the equation. I'll use base 10 as it's built-in to a calculator and fairly easy to understand.
To change bases (from a to b), you use the following formula:
log(base a)x = log(base b)x / log(base b)a.
So for your specific example, you have:
log(base 3)24 = log(base 10)24 / log(base 10)3
= 1.3802 / 0.4771
= 2.8929
For the second part, you don't need to change the base as:
log(base a)a = 1
So filling in the numbers:
log(base 3)24 - 3log(base 2)2
= 2.8929 - 3
= -0.1071
Hope that helps.
Rewrite as: Logb x^5 - Logb y^(1/4)+ Logb z^2 Use the rules to get: Logb (x^5/y^(1/4))*z^2) The addition signs correspond to multiplying and the subtraction signs correspond to division. You can check your answers on a calculator by substituting numbers such as x=3, y=5, and 7=z and 10 for b (you can use the LOG key on your calculator) or use (exponential) e and the LN key. You should get the same answers for both the original and simplified equation.
log(base 3)24 - 3 log(base 2)2 = log24/log3 - 3
since log (base 2) 2 = 1
change of base is:
log(base 3)24 = log24/log3
[log (base 3)24] - [3 log(base 2)2]
= [log (base 3)24] - 3
= [log (base 3)24] - [log (base 3)27]
= log (base 3) (24/27)
= log (base 3) (8/9)