If you connect a 33 Ω resistor in parallel with a 120 Ω resistor, a 1000 Ω resistor and a 9 V battery, which resistor will have the most current flowing through it?
resistors in series divide the voltage the current stays the same throughout, in parallel they divide the current, and the voltage remains unchanged, the larger the resistor the more current it draws
as resistors in parallel are product over sum or 1/R1 + 1/R2 = Rt you have a combined resistance of 25.229 ohms, which will draw 0.3567 amps,
9/33R = 0.2727273a 9/120R = 0.075a 9/1000R = 0.009a added together makes 0.3567 amps.
Answers & Comments
In parallel arrangement, all resistors have the same voltage drop, so by Ohm's Law:
I = V/R the resistor with the SMALLEST value will have the largest current (I). ANS
resistors in series divide the voltage the current stays the same throughout, in parallel they divide the current, and the voltage remains unchanged, the larger the resistor the more current it draws
as resistors in parallel are product over sum or 1/R1 + 1/R2 = Rt you have a combined resistance of 25.229 ohms, which will draw 0.3567 amps,
9/33R = 0.2727273a 9/120R = 0.075a 9/1000R = 0.009a added together makes 0.3567 amps.