Verified answer

In hydrogen sulfide H2 weighs 2g and S weighs 32g so if you have 2g of H2 you have 32g of S > 32/2=16

so answer 16*0.384=6.144g

Hydrogen Sulfide Decomposition

6.5-0.384=x

Law of conservation of mass :) must always end up with how much you started with.

Then if you wanted to know how many moles: 6.5-0.384=6.116, 6.116/32 (Molar mass of sulfur)=0.191125 mols of S. However I'm pretty sure sulfur is a diatomic molecule naturally, you actually have 0.0956 mols of S2

use the equivalent equation i.e H2S<=>2H+S.as this is fully decomposed, so ( weight/eq.weight of H2S ) = ( weight /eq.weight of hydrogen ) + ( weight/eq. weight of sulfur ),so weight of sulfur here is unknown,and hope you know how to find eq weight,its (eq.weight=atomic weight/n factor).