A tank contains 11.8 g of chlorine gas (Cl2) at a temperature of 87 °C and an absolute pressure of 5.40 × 105 Pa. The mass per mole of Cl2 is 70.9 g/mol. (a) Determine the volume of the tank. (b) Later, the temperature of the tank has dropped to 27 °C and, due to a leak, the pressure has dropped to 3.20 × 105 Pa. How many grams of chlorine gas have leaked out of the tank?
My answer for part A is correct, but I can't seem to get B right.
A) V= 9.146e-4 m^3
Here's the work I did for part B:
11.8 g - (3.20e5 Pa) (9.146e-4 m^3)
----------------------------------------- X 70.9 g
(8.314 J/mol K ) (273 +27)
11.8 g - 8.31947g= 3.481 g
My answer is 3.481 g, and I'm still wrong. Any ideas anyone? Please and thank you!
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Answers & Comments
Verified answer
Hmm. I get 9.23x10^-4 m^3 for A. That's a significant difference.... I'm going to use that in B.
PV=nRT
n = PV/RT
n = (3.20x10^5 Pa) (9.23x10^-4 m^3) / (R 300K)
n = 0.1184 mol
m = n mw
m = 0.1184mol * 70.9g
m = 8.395g
Subtracting from 11.8g
m = 3.41g
So I don't see anything wrong with your technique.