Ideal Gas Law Problem help?
Find the temperature of 12 moles of a gas if the volume is 48-L and the pressure is 380 mmHg?
I understand the problem, but I'm confused as to what my teacher meant when she said I had to divide 380mmHg by the stp 760mmHg before putting it into the final problem and if another problem had atm I would have to subtract the given atm from stp atm which is 1, so why do I have to do that and how?
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You use the Gas Law Equation:
PV = nRT
But it is important that you get the units correct for the chosen R constant. I think that the most common units here are:
P = pressure in atm : 380mmHg = 380/760 = 0.5 atm
V = volume in litres = 48.0L
n = moles = 12.0
R = constant = 0.082057
T = temperature - what you want . But remember that the answer will give the temperature in Kelvin
Substitute:
0.5*48 = 12*0.082057*T
24 = 0.985T
T = 24*0.985
T = 24.4
This is a very low temperature: In °C it is : -273 +24.4 = - 248.6°C.
Check that you have submitted the data correctly.