Ideal gas law problems?
a.)When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction
CaCO3(s)→CaO(s)+CO2(g)
How many grams of calcium carbonate are needed to produce 39.0L of carbon dioxide at STP?
b.)Butane, C4H10, is a component of natural gas that is used as fuel for cigarette lighters. The balanced equation of the complete combustion of butane is
2C4H10(g)+13O2(g)→8CO2(g)+10H2O(l)
At 1.00 atm and 23 ∘C, how many liters of carbon dioxide are formed by the combustion of 3.20g of butane?
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Verified answer
a.)
( 39.0 L CO2) / (22.414 L/mol) x (1 mol CaCO3 / 1 mol CO2) x
(100.0875 g CaCO3/mol) = 174 g CaCO3
b.)
(3.20 g C4H10) / (58.12259 g C4H10/mol) x (8 mol CO2 / 2 mol C4H10) =
0.22022 mol CO2
V = nRT / P = (0.22022 mol) x (0.08205746 L atm/K mol) x (23 + 273 K) / (1.00 atm) =
5.35 L CO2