Verified answer

You have to know some formulae,I cant derive them for you but you can google them - "Projectile motion"

Taking u=27m/s ,

@=30,

g=10m/s^2 (acceleration due to gravity)

a)Time=2usin@/g=2x27sin(30)/10=2.7s (sin30=1/2)

b)max height=u^sin^2@/2g=27x27sin^2(30)/2x10=9.25m

c)Range=u^2sin(2@)/g=27x27sin(60)/10=64.35m

Hope this helps!

First find the horizontal and vertical components of the velocity vx = vcostheta = 27 cos30 = 23.4 m/s and viy = vsintheta = 27 sin30 = 13.5 m/s

a) To find total time I usually put deltaY = 0 (you start on the ground and end on the ground)

the equation is deltaY = viy t + 1/2 gt^2 so 0 = 13.5 t - 4.9 t^2 solve for t (2.76 s)

For maximum height find deltaY at half the hang time ( t= 2.76/2 = 1.38 s) deltaY = 13.5 (1.38) - 4.9 (1.38^2) = ???

for the range find delta X = vx t for the total hang time = 23.4 x 2.76 = ???

Who's McCallum??

If that is algebra-depending physics, evaluation algebra and geometry. If that is calculus-depending, evaluation algebra, geometry, and calculus. maximum those who've difficulty with physics are having difficulty with the maths, a minimum of for the intro classes. some thing is merely learning to coach the concepts. learn what speed, acceleration, stress, pressure, and friction are. you'd be predicted to understand some undemanding concepts, regardless of the indisputable fact that that is no longer a demanding direction in case you install some attempt.