Log(x+3)= logx+log3
log[(x+3)/3x] = 0
(x+3)/3x = 10^0 = 1
3x = x+3
x = 3/2
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log[(x+3)/3x] = 0
(x+3)/3x = 10^0 = 1
3x = x+3
x = 3/2