logarithm question precalculus?
(.15)(2^t/14) = 1 solve for t some how u use logs
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(.15)(2^t/14) = 1 solve for t some how u use logs
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log.15 + log2^t -log14 = log1
log.15 + t -log14 = log1
t=log1+log14-log.15 (all base 2)
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