1. Coefficients will also be put into powers, so 3log5(2) becomes log 5(2 cubed). Now adding separate logs is solely multiplying the within components together, so it can be log 5(2 cubed instances 7) which offers you log 5(fifty six) 2. Comply with the same line of idea from difficulty one, but be aware of that subtracting separate logs is dividing. 2log8 equals log 64. So log(64*9/36) three. Rectangular root of 9 is three. Log base of any quantity of any number is just 1.

2 log [a] X - 3 log [a] y = log[a] (X^2)/(y^3)