Solve the equation.
log (3 + x) - log (x - 3) = log 3
log (3 + x) - log (x - 3) = log 3;
Log quotient rule:
log [(3+x) / (x-3)] = log 3;
Raise both sides to power of 10:
10^log [(3+x) / (x-3)] = 10^log 3;
Now solve for x:
(3+x) / (x-3) = 3;
3+x = 3x - 9;
12 = 2x;
x = 6.
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log (3 + x) - log (x - 3) = log 3;
Log quotient rule:
log [(3+x) / (x-3)] = log 3;
Raise both sides to power of 10:
10^log [(3+x) / (x-3)] = 10^log 3;
Now solve for x:
(3+x) / (x-3) = 3;
3+x = 3x - 9;
12 = 2x;
x = 6.