here's the equation
4 = -log [x]
how would i find x
4 = log x^(-1)
10^4 = x^-1
x = 1/10000
Assume log is log to base 2 in the following :-
- 4 = log x
x = 2^(- 4)
x = 1 / 16
multiply both side by -1 to get log[x]=-4
take apply the exponential function to both sides to get
10^(log[x]) = 10^(-4)
which simplifies to [x] = 10^(-4).
So, x = plus or minus 10^(-4)
You guys forgot about the absolute value. I'm the only one ot give the right answer and I get two thumbs down? What gives?
- log(a)= log(1/a)
4 = log|x^-1|
4 = log|1/x|
10^4=1/x
x= 10^-4
x=1/10000
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Verified answer
4 = log x^(-1)
10^4 = x^-1
x = 1/10000
Assume log is log to base 2 in the following :-
- 4 = log x
x = 2^(- 4)
x = 1 / 16
multiply both side by -1 to get log[x]=-4
take apply the exponential function to both sides to get
10^(log[x]) = 10^(-4)
which simplifies to [x] = 10^(-4).
So, x = plus or minus 10^(-4)
You guys forgot about the absolute value. I'm the only one ot give the right answer and I get two thumbs down? What gives?
- log(a)= log(1/a)
4 = log|x^-1|
4 = log|1/x|
10^4=1/x
x= 10^-4
x=1/10000