Oppositely charged parallel plates are separated by 5.37 mm. A potential difference of 600 V exists between the plates.
I need help answering the following questions.
(a) What is the magnitude of the electric field strength between the plates?
(b) What is the magnitude of the force on an electron between the plates?
(c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.91 mm from the positive plate?
Any help would be greatly appreciated.
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Verified answer
A. E = ΔV/d = 600/0.00537 v/m (or N/C) (note direction is from + to -)
B. F = EQ; Q(e-) = -1.602E-19 C (note direction is opposite to direction of E because Q is negative)
C. W = Fd = F(0.00537-0.00291) J (this is a positive quantity since the electron is repelled by the neg. plate)
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