Parallel and perpendicular lines - algebra 1......can anyone please help me?
im not sure what to do and i dont get it much and i was wondering what do i do with this.......
"write the slope intercept form of an equation of the line that passes through the given point and is parallel to the graph of each equation"
(2,-1), y=2x+2
(4,-1), y=2x+1
(3,3), y=2/3x-1
(-1,2), y=-1/2x-4
(2,2), 3y=-2x+6
(2,2), 3x-4y=-4
More Questions From This User See All
Answers & Comments
Verified answer
If a line is parallel to another line it has the same slope. So look at your equation and figure out the slope. Then use that slope and the given points to create your new equation, using the point-slope form.
(y-(ycoordinate))=m(x-(xcoordinate))
Where m is slope.
So for the first one, the slope is that equation can be found by using the form y=mx+b, where m is slope and b is y intercept.
y=2x+2; 2 is the slope.
Put this into point-slope form and you get:
y-(-1)=2(x-2)
y+1=2x-4
y=2x-5
parallel lines have the same slope
perpendicular have opposite slope for instance
if the slope was 7 for one line the perpendicular would be -1/7
so u make it negavtive if positive and positive if negative
and you would take the reciprocal of it also