Perpendicular Lines! A level Maths!?
Well, I can't do this question, and my teacher refuses to help me because she expects me to know it. But I don't SO YEAH.
So, i was wondering if someone to explain it to me and help me solve it.
The straight line L1 has equation y=3x+2
The line L2 is perpendicular to L1 and passes through thr point (-2,6)
a) Find an equation of the line L2 in the form ay+bx=c
These lines L1 and L2 intersect at poin C
b) Use an algerbraic methold to determine the co-ordinates of C
The lines L1 and L2 cross the y axis at the points A and B, respectively.
c) Find the exact value of the area of the triangle ABC
Please helpp!
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In order to get a perpendicular line, the "b" has to be the inverse of itself. That means that it is -1/3 because to get the inverse you need the number that when multiplied together, gives you -1 as an answer. Hopefully that can at least give you a start. Your "c" for L2 will be where the line intersects the y axis. The the area of the triangle will be 1/2 it's base length time it's height.
a) parallel lines have the comparable gradient. hence in (a million) the coefficient of 'x' is two, - that's the gradient of the line. for this reason for (2) 3x + py = 14 py = -3x + 14 y = -3/p(x) + 14/p So for lines a million & 2 to be parallel then 2 = -3/p p = -3/2 careful with this one :: -3 divided by employing -3/2 = 2 b) for lines to be perpendicular they could fulfill the equation mm' = -a million (the place m & m' are the gradients) So employing (a million) Gradient 2 then 2 x m' = -a million m' = -a million/2 (gradient of (2) perpendicular to (a million)).