Photon energy problem?
Photon energy problem?
Sodium metal requires a photon with a minimum energy of 4.41 10-19 J to emit electrons.
(a) What is the minimum frequency of light necessary to emit electrons from sodium via the photoelectric effect?
(b) What is the wavelength of this light?
(c) If sodium is irradiated with light of 405 nm, what is the maximum possible kinetic energy of the emitted electrons?
(d) What is the maximum number of electrons that can be freed by a burst of light whose total energy is 1.00 µJ?
Answers & Comments
Verified answer
E = hf
so f = E/h = 6.66×10^14 Hz
fl = c
so l = c/f = 4.50×10^-7 m
E = hc/l = 4.91×10^-19 J
1.00×10^-6/4.41×10^-19 = 2.27×10^12 electrons
you have distinctive typos sriebe, this is going to be (10^-6)/(4.91x10^-19J) = 2.04x10^12 you merely take the full means and divide it with the aid of the means consistent with photon which you got here upon previously interior the priority
1. E=h*nu
2. 3.0X10^8 m/s = (lambda)*(nu)
3. E=h*c/lambda
4. I am not getting that one....it seems like you need what is holding the electron(s)