Verified answer

The work energy theorem tells you that work is the integral of force over the path the particle moves. So you have a force F, and a path of lenght l = 0.0015 m, so the work done is

W = F*l = 4x10^-3 N* 0.0015m = 6x10^-6 J

Now that energy is equal to the potential energy between point A and B adn that is given by:

W = qV where q = 2x10^-6 C and V is the potential difference. So

V = W/q = 6x10^-6 N/2x10^-6 C = 3 V

Hi

the work done = potential gained.

Fd=QV

V = Fd/Q

V = 3 J/C

which you will notice is the same as volts.

potential difference, V= E*d (Electric field * distance between them)

=(F/q)*d

Calculate with the values, u will get the answer