Verified answer

Rifle mass?

OK!.

Starting at the beginning:

(0.0179 x 943)/6.33 = V of rifle of 2.667m/sec.

Acceleration to stop in 0.0203m. = (v^2/2d) = -175.1943m/sec^2.

Force = (ma) = 6.33 x 175.1943, = 1108.98N.

a million. This comes from conservation of momentum. in the previous you fired the bullet, the gun-bullet momentum became 0. After the bullet is shot, it is going off in one course with a undeniable momentum (mass x velocity); to look after momentum after capturing the gun ought to balk with an identical momentum in the alternative course (Newton's third regulation says that's going to be opposite) so the entire momentum remains 0. because of the fact the gun is extra huge than the bullet, this is balk is small, and your hand can end this is action certainly. 2. The parachute create an excellent floor section to create extra drag rigidity than a human physique fallinbg via the air. This has the end results of heavily lwering your terminal velocity - the optimum velocity you attain once you fall from a great top, that's an result that occurs once you combine gravity with opposing air resistance. So a smaller terminal velocity ability the skydiver falls at a slower value and can land without breaking his/her bones. 3. the pushing rigidity mandatory is F= coeff x regularly occurring rigidity. all of us comprehend that F = weight = W We additionally comprehend that ordinary rigidity = mg = W = weight, additionally! hence, coeff. = F / NormalForce = W / W = a million Ans: coeff of sliding friction = a million