A single slit diffraction pattern was made with light with λ = 510 nm. The screen was 1.8 m from the slit. If the slit had a width 10 mm, what is the width w of the central maximum in cm?
Once again:
λ=sf/x
Where λ is the wavelength, s is the slit separation, f is the fringe width and x is the slit to screen distance.
Rearrange: f=λx/s
f=(510e-9)(1.8)/(10e-3)=9.18 X 10^-5
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Verified answer
Once again:
λ=sf/x
Where λ is the wavelength, s is the slit separation, f is the fringe width and x is the slit to screen distance.
Rearrange: f=λx/s
f=(510e-9)(1.8)/(10e-3)=9.18 X 10^-5