Physics parallel circuit problem?
Okay so in this problem there is a parallel circuit with two resistors. Resistor one has 12 ohms and we don't know about resistor two. There is a 24 volt source and an ammeter. we also know that the current near resistor two is 6 amperes and the ammeter is closer to resistor two. The problem is asking about the current in the ammeter. I am thinking that the answer is 6 amperes but the book tells me the answer is 8 amperes. Can anyone explain why?
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OK, here's the way that I think the circuit is setup that you're describing: The source voltage is 24 volts dc. The amp-meter is connect between the battery and the two parallel resistors. The amp-meter reads total circuit current.
The voltage across both parallel resistors is the same voltage as the 24 volt dc source. Thus, the current flowing in the first resistor, R1, branch is simply: E / R1
The current flowing in the second resistor, Rx, branch is: E / Rx
The circuit amp-meter reads total circuit current, It, which is the sum of the currents flowing in both parallel resistor network, I1 + Ix
Then Ix = It - I1
The resistor, Rx, is equal to: E / Ix
The circuit current meter reading will always be larger than either resistor branch current.
Besure that you are readiing the question right. Is it asking you for total circuit current? Or is it asking you for the current flowing through Rx? The current flowing in Rx will be less than the total circuit current. However, when the current through Rx is added to the current flowing through R1, that current should then equal the circuit current.
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Resistance = potential.difference across the wire divison current trough the wire
wattage W = V^2/R you probably did not factor out voltage, may be you should apply standard loved ones voltage 220V get resistance R of each and every equipment, then get cutting-edge in each and each and every of them utilizing I = V/R