A window has a glass surface of 4320 cm2 and a thickness of 3.6 mm. Find the rate of energy transfer by conduc-
tion through this pane when the temperature of the inside surface of the glass is 73◦F and the outside temperature is 94 ◦F. Assume the thermal conductivity of window glass is 0.8J/s·m·◦C.
Answer in units of kW
part b
Find the rate of energy transfer for the same inside temperature and an outside tempera- ture of 0◦F.
Answer in units of kW
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Answers & Comments
Verified answer
I think you need to apply Fourier's Law, which gives the "heat flow rate" across a homogeneous material between two endpoints, each of which is at a constant temperature (see Source 1):
(1) ΔQ / Δt = - κ * A * ΔT / Δx,
where:
ΔQ / Δt = heat flow rate in W (to be calculated)
κ = thermal conductivity in W / m·◦C = 0.8 (given)
A = surface area = 4320 cm^2 (given) in m^2
ΔT = the difference in temperature between the two endpoints = Tto - Tfrom in C
Δx = the distance between the two endpoints = the thickness of the glass = 3.6 mm in m
Now, simply convert the given values to their proper units as indicated, plug them into equation (1), which will give watts, and divide by 1000 to get kW. Pay attention to the signs, as the flow rates in (a) and (b) are in opposite directions.
Converting the values given where necessary:
(2) A = 4320 cm^2 = 0.432m^2
(3) ΔT = Tin - Tout = (73 - 94)F = (5/9) * (73 - 94) C = -11.7C
(4) Δx = 3.6 mm = 3.6e-3m
Substituting in (1):
(5) ΔQ / Δt = - 0.8 * 0.432 * (-11.7 / 3.6e-3)
= 1123.2W or
= 1.12kW is the energy transfer by conduction---part (a), positive from outside to inside
For part (b) we have a different temperature difference, so we need to modify (3):
(6) ΔT = Tin - Tout = (73 - 0)F = (5/9) * (73 - 0) C = 40.6C
Notice the difference in sign. Recalculating,
(7) ΔQ / Δt = - 0.8 * 0.432 * (40.6 / 3.6e-3)
= -3897.6W or in kW and rounding,
= -3.90kW is the energy transfer by conduction---part (b), negative from outside to inside, therefore the (positive) flow is from inside to outside, as you would expect.
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