ok so i have to calculate the work done by the frictional force during the skid.this is the kinetic energy of the truck and car just after the impact
skid marks: 22.0m
side of car: dented 0.60m
truck: hardly dented
mass of truck and driver: 2700kg
mass of car and driver:1200kg
force needed to pull car sideways: 6900N
ok so how do i work out the work done by the frictional force?? :S
so confused on this right now
please show method
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Answers & Comments
Verified answer
Not enough information. Most important would be the coefficient of friction between the tires and the roadway.
Otherwise you'd need starting and ending energies. Without entry speed, you don't have starting energy. Without information on how much work is done during the deformation, you don't have ending energy.
Are the skid marks from the truck or the car? Assuming the truck:
W = F(f) * d
W = F(N) *mu * d
W = g*2700kg * mu * d
W = (9.81m/s^2)(2700kg) mu * 22m
W = 583000J * mu
One site, http://www.engineeringtoolbox.com/friction-coeffic... suggests that dry tires have a coefficient of friction near 1. If so:
W = 5.83x10^5J
i am not quite sure but i feel skid marks of 22 m has no role work done is given by f.ds .the force is 6900n and 0.6m of movement as when car and truck moved together after docking...
work done= 2900*0.6 j=1740 J