Oxalic acid is a weak acid, which means that it has two finite Ka's.
H2C2O4 ===> H+ + HC2O4- Ka1 = 3.8 x 10^-2
HCO4- ===> H+ + C2O4= Ka2 = 5.0 x 10^-5
You usually know what is the approximate concentration of H2C2O4 in advance, so you use that estimate. Then you use Ka1 and Kw (1.0x10^-14) to calculate the pH of the NaHC2O4 solution, which is the first equivalence point. Next you use Ka2 and Kw to calculate the pH of Na2C2O4 solution, which is the second equivalence point.
quantity a million is C. The weaker the backside the decrease the Kb fee quantity 2 is B. vulnerable base/acids often have good conjugate acid/base quantity 3 is D. you purely blend the recommendations an you stumble on that each and every of the NaOH is neutralized yet some HCl is left after which you purely take the -log of that conc and locate that the respond is 0.6
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Oxalic acid is a weak acid, which means that it has two finite Ka's.
H2C2O4 ===> H+ + HC2O4- Ka1 = 3.8 x 10^-2
HCO4- ===> H+ + C2O4= Ka2 = 5.0 x 10^-5
You usually know what is the approximate concentration of H2C2O4 in advance, so you use that estimate. Then you use Ka1 and Kw (1.0x10^-14) to calculate the pH of the NaHC2O4 solution, which is the first equivalence point. Next you use Ka2 and Kw to calculate the pH of Na2C2O4 solution, which is the second equivalence point.
quantity a million is C. The weaker the backside the decrease the Kb fee quantity 2 is B. vulnerable base/acids often have good conjugate acid/base quantity 3 is D. you purely blend the recommendations an you stumble on that each and every of the NaOH is neutralized yet some HCl is left after which you purely take the -log of that conc and locate that the respond is 0.6
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