When a 13.2-kg mass is placed on top of a vertical spring, the spring compresses 5.93 cm. Find the force constant of the spring?
From Hooke's Law: F = kx
The force on the spring is the weight of the object, 13.2*9.8 = 129 N
x = 5.93 cm =0.0593 m
129 = (0.0593)x
x = 2181 N/m
Spring constant (k) is normally measured in N/m so you need to convert the mass to force.
So, k = 13.2 x 9.81 / (5.93/100) = 2184 N/m
The 13.2 kg mass produces a force F= m*g on the spring
F= (13.2 kg)(9.8 m/sec^2) = 129.4 Newton
The spring constant k is found from
F = k*(5.93 cm)
k = 129.4 N/5.93 cm = 21.8 N/cm
13.2/5.93 = 2.226
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Verified answer
From Hooke's Law: F = kx
The force on the spring is the weight of the object, 13.2*9.8 = 129 N
x = 5.93 cm =0.0593 m
129 = (0.0593)x
x = 2181 N/m
Spring constant (k) is normally measured in N/m so you need to convert the mass to force.
So, k = 13.2 x 9.81 / (5.93/100) = 2184 N/m
The 13.2 kg mass produces a force F= m*g on the spring
F= (13.2 kg)(9.8 m/sec^2) = 129.4 Newton
The spring constant k is found from
F = k*(5.93 cm)
k = 129.4 N/5.93 cm = 21.8 N/cm
13.2/5.93 = 2.226