given g(x)=x^2-x, what is g(1-x).............I got x^2-x(but then again im usually wrong)
g(1- x) = (1 - x)² - (1 - x)
=1 - 2x + x² - 1 + x
= x² - x
you are correct
I got the same thing so it looks like you got it right this time! Way to go Idaho(or whatever state you live in)!
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g(1- x) = (1 - x)² - (1 - x)
=1 - 2x + x² - 1 + x
= x² - x
you are correct
I got the same thing so it looks like you got it right this time! Way to go Idaho(or whatever state you live in)!