For a camera with a lens of fixed focal length F to focus on an object located a distance x from the lens, the film must be placed a distance y behind the lens, where F, x, and y are related by
1/x+1/y=1/F
suppose the camera has a 55-mm lens (F=55)
a. Express y as a function of x
b. What happens to the focusing distance y as the object moves far away from the lens?
c. What happens to the focusing distance y as the object moves close to the lens?
Thanks!! :)
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Verified answer
It's easier to find an identity if you get rid of that inversion. So first multiply everything by Fxy.
Fxy(1/x + 1/y) = Fxy(1/F)
F(xy/x + xy/y) = xy(F/F)
F(y + x) = xy
Now you're asked to put everything in y= format. So break apart every term that has a y into y times f(C, x) form (in other words, y times terms that only contain a constant or x), like this:
y(F) + Fx = y(x)
Now it's very easy to turn it into a function in terms of y.
y(F) + Fx - Fx = y(x) - Fx
y(F) = y(x) - Fx
y(F) - y(x) = y(x) - y(x) - Fx
y(F) - y(x) = -Fx
y(F - x) = -Fx
y(F - x) / (F - x) = -Fx / (F - x)
y = -Fx / (F - x)
Now for B and C, draw up some values for X in a table. For x, you should pick:
* a very large negative number (between negative infinity and -5)
* -1
* a very small negative number (between -1 and 0)
* zero
* a very small positive number (between 0 and 1)
* 1
* a very large positive number (between 5 and infinity)
And just look at what you get for y when you plug those into the equation.