1. triangle ABC has vertices A(2,1), B(7,4) and C(4,-1). DEF has vertices D(-3,1) D(0,-4), and F(-5,-1). use the distance formula to prove that triangle ABC=DEF
2.GIVEN: BAC=DAC, DCA=BCA
PROVE: BC=CD
3.GIVEN: ABE=CBE and AEB=CEB
PROVE: AB=CB
4.GIVEN: BAC=DAC, B=D
Prove:BC=DC
5.GIVEN: DCA=BCA, B=D
PROVE:AB=AD
if u could do any of them thats greatt!!! i just really need help :/
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Answers & Comments
Verified answer
d=sqrt((x2-x1)^2+(y2-y1)^2)
AB=sqrt((7-2)^2+(4-1)^2)=
sqrt34
continue