Verified answer

y = x² - 4x

y = (x - 2)² - 4

h = 2 and k = -4

y=x^(2)-4x

To create a trinomial square on the left-hand side of the equation, add a value to both sides of the equation that is equal to the square of half the coefficient of x. In this problem, add (-2)^(2) to both sides of the equation.

y=x^(2)-4x+4

Factor the perfect trinomial square into (x-2)^(2).

y=(x-2)^(2)

Factor the perfect trinomial square into (x-2)^(2).

y=(x-2)^(2)-4

This is the form of a paraboloa. Use this form to determine the values used to find vertex and x-y intercepts.

y=a(x-h)^(2)+k

Use the standard form to determine the vertex and x-y intercepts.

a=1_k=-4_h=2

You do these problems by using the method of completing the square.

y = (x^2 - 4x +_____) - ______

y = (x^2 - 4x + 4 ) - 4

y = (x - 2)^2 - 4