4log(subscript) m - log subscript n
and also
log(subscript6) 5 + log(subscript6) X
how do i solve theseee as a single logarithm?
4logm-logn = log(m^4/n)
when subtracting logs, you divide them as a single logarithm
log base 6 of 5 + log base 6 of x= log base 6(5x)
multiply when you add logarithms
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4logm-logn = log(m^4/n)
when subtracting logs, you divide them as a single logarithm
log base 6 of 5 + log base 6 of x= log base 6(5x)
multiply when you add logarithms