Verified answer

formula: v^2 = u^2 - 2gh

where

v = final velocity

u = initial velocity

the acceleration of gravity is g = 9.8 m / s^2

h is the height

at max height

0^2 = u^2 - 2gh

or

u^2 = 2gh

h = u^2 / (2*g)

h = u^2 / (2g) = 2^2 / (2 * 9.8) = 0.2041 meters

at max ht velocity becomes zero.

Formula is v^2 = u^2 + 2*a*s

V=final velocity=0

u=initial velocity=2

a=acc due to gravity=MINUS 9.81 m/s^2

s= reqd distance

so u can find