Verified answer

1)

x=6^(y) y=log(na base de 3) 2 . log(na base de 6) 3?

=>

x = 6^y

y = log(6) x

y = log x / log 6

e

y = log(3) 2 . log(6) 3

y = (log 2 / log 3) * (log 3 / log 6)

y = log 2 / log 6

Então:

log x / log 6 = log 2 / log 6

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x = 2

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