using separating variables solve
1)
cos^2x(dy/dx)=y+3
2)
sinx/1+y * dy/dx=cosx
any help is much appreciated
1.
dy/(y+3)=dx/(cos^2x)
dy/(y+3) =sec^2x dx
dy/(y+3) -sec^2x dx=0
ln|y+3| - tanx =k
ln (y+3) = tanx +k
y+3 = e^(tan x + k)
y = e^(tan x + k) - 3
sinx/(1+y) * dy/dx=cosx
dy/(1+y) =cotx dx
dy/(1+y) -cotx dx=0
ln(1+y) -ln(sinx) = C
ln((1+y)/sinx)=C
(1+y)/sinx=e^C
1+y=e^C sinx
y=e^C sinx - 1
Sorry its late at night here, I'm tired and I'm not sure this one is right - just took its derivative and it didn't look like the differential eqn. Check it!!
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Verified answer
1.
cos^2x(dy/dx)=y+3
dy/(y+3)=dx/(cos^2x)
dy/(y+3) =sec^2x dx
dy/(y+3) -sec^2x dx=0
ln|y+3| - tanx =k
ln (y+3) = tanx +k
y+3 = e^(tan x + k)
y = e^(tan x + k) - 3
2)
sinx/(1+y) * dy/dx=cosx
dy/(1+y) =cotx dx
dy/(1+y) -cotx dx=0
ln(1+y) -ln(sinx) = C
ln((1+y)/sinx)=C
(1+y)/sinx=e^C
1+y=e^C sinx
y=e^C sinx - 1
Sorry its late at night here, I'm tired and I'm not sure this one is right - just took its derivative and it didn't look like the differential eqn. Check it!!