Find the sum of the sequences. I would prefer for you to explain how to do it instead of just answering but any help is welcome.
3,6,12,......12,288
117,110,103...,33
42,-7,(7/6)....., 42(-(1/6)^9
Also find the sum of the first n terms of the sequence.
14,8,2.. ;n=9
6,-3,(3/2),(-3/4)...; n=11
I have an idea but dont completely understand please help.
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Verified answer
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1) this is geometric series
sn=a1(1-r^n)/(1-r)
an=a1r^(n-1)
a1=3
r=2
an=288
solve for n and then solve for sn