OK. You're given f(9) = 2. If you want to find a point on the graph of y = f(x-3) + 5 then you
have to set x-3 = 9 and that gives you x = 12. and you know that f(x-3) = f(9) = 2 so the y in your ordered pair is 2+5 = 7. Hope this explains how to do this type of problem.
The question is written poorly. the difficulty is this may be the two 6/(2(a million+2)) which = a million or (6/2)(a million+2) which = 9. because of the fact it is not clarified the two solutions are justified, and once you bump into a majority of those questions on line merely ignore approximately them, there is not any factor arguing approximately it. If in spite of the shown fact which you bump into the form of question in a valid place (i.e. a textbook or a try) often you will possibly desire to have the capacity to tell from the format. as an occasion, if the difficulty replaced into arranged as a fragment with 6 in the numerator and 2(a million+2) in the denominator then the respond could be a million, in spite of the shown fact that if it replaced into arranged with a fragment 6/2 being prolonged by utilising (a million+2) then the respond could be 9. No valid source could present day the difficulty to you in the way shown on your question. Tl;dr: Poorly written question, the two answer is optimal, ignore approximately debate
Answers & Comments
OK. You're given f(9) = 2. If you want to find a point on the graph of y = f(x-3) + 5 then you
have to set x-3 = 9 and that gives you x = 12. and you know that f(x-3) = f(9) = 2 so the y in your ordered pair is 2+5 = 7. Hope this explains how to do this type of problem.
The question is written poorly. the difficulty is this may be the two 6/(2(a million+2)) which = a million or (6/2)(a million+2) which = 9. because of the fact it is not clarified the two solutions are justified, and once you bump into a majority of those questions on line merely ignore approximately them, there is not any factor arguing approximately it. If in spite of the shown fact which you bump into the form of question in a valid place (i.e. a textbook or a try) often you will possibly desire to have the capacity to tell from the format. as an occasion, if the difficulty replaced into arranged as a fragment with 6 in the numerator and 2(a million+2) in the denominator then the respond could be a million, in spite of the shown fact that if it replaced into arranged with a fragment 6/2 being prolonged by utilising (a million+2) then the respond could be 9. No valid source could present day the difficulty to you in the way shown on your question. Tl;dr: Poorly written question, the two answer is optimal, ignore approximately debate
(12, 7)