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Greetings,

32 * 10^-3 g of unknown powder

of which

H = 2.6 divide by 1 giving about 2.6 moles of H

P = 6.7 divide by 31 giving about 0.216 moles of P

O = 13.7 divide by 16 giving about 0.85 moles of O

(all the 10^-3 are still there multiplying the moles)

assuming the rest is completely N

N = 9 divide by 14 giving about 0.643 moles of N

now divide by the smallest number of moles to get

H = 12

P = 1

O = 4

N = 3

the simplest empirical formula is N3H12O4P

Regards.

First multiply everything by 10^4 so that the numbers are easier

320 g = x + 26g + 67g +137g --> x = 90

Now you just have to find the greatest common divider of all these numbers and divide all of them by that, in this case that is easy because 137 is prime and hence the GCD of all the numbers has to be 1.

so

to make 320 of the substance get

90g nitrogen

26g hydrogen

67g phosphorous

137g oxygen.