Verified answer

6(2x+y)+2(x+9)

12x + 6y + 2x + 18

14x + 6y + 18

Okay enough telling you, time to SHOW you.

6(2x+y) + 2(x+9)

**First you have to get it out of ( ) form. Use the disturbitive property.**

1) Mulitply 6*2x = 12x

2) Multiply 6*y = 6y

3) Multiply 2*x = 2x

4) Multiply 2*9= 18

So you have 12x+6y + 2x +18

You have 2 x-variables. Put the x's together (combine like terms).

14x+6y+18

Some teachers want it in SIMPILEST form. This is for Algebra mainly, I don't think pre-alg requires but just in case.

You can take 2 out of each of those variables.

So...

2(7x+6y+9) you don't know what x and y are, so this is as LOW as you can go.

There you go ^_^ not only did I catch your fish but I'm teaching you how to fish so you can eat forever!

I have already tried to explain a few of these problems for you, so hopefully you are actually reading these to try to understand.

Again, this problem uses the distributive property.

6(2x + y)

6 * 2x = 12x

6 * y = 6y

12x + 6y

2(x + 9)

2 * x = 2x

2 * 9 = 18

2x + 18

12x + 6y + 2x + 18 which equals out to be

14x + 6y + 18

6(2x+y) + 2(x+9)

12x + 6y + 2x + 18

14X + 6y + 18 = 0

Multiply what's outside the parentheses by what's in them and then add like values (e.g., 12x and 2x).

Have a great day!

12x + 6y + 2x + 18

14x + 6y + 18

you have to take it in steps. First multiply out.

(12x + 6y) + (2x + 18)

then combine like terms.

14x + 6y + 18

I hope that helps! You can use that method to simplify all problems of this kind.

12x+6y +2x+18

=14x+6y+18

12x + 6y + 2x + 18

= 14x + 6y + 18

Distrubutive Property.

12x + 6y + 2x + 18

14x + 6y + 18

7x + 3y + 9 or 2(6x+3y+9)

well suppose x=1 and y=1, now first of all multiply 2 with 1, u get 2, add 1, 6(2x1+1)+2(1+9)= 38