Verified answer

Using laws of logarithms,

log(a)-log(b)=log(a/b)

log(a)+log(b)=log(ab)

Therefore,

log(x)-log(y)+log(x^2)

log(x/y)+log(x^2)

log(x(x^2)/y)

log(x^3/y)

og(x) - log(y) + log(x^2)

=> log(x.x^2 / y)

=> log(x^3 / y)

log(x) - log(y) + log(x^2)

=> log(x.x^2 / y)

=> log(x^3 / y)

log((x^3)/y) within the range of defination

use loga+logb=loga*b

loga-logb=loga/b