Verified answer

x^2y/3x^5y

x*x *y/3*x*x*x*x*x*y

1/3*x*x*x

1/3x^3

The y's cancel out, so x^2/3x^5.

Elimate a power from both, leaves x/3x^4

( x^2 ) ( y )

------------------

3 ( x^5 ) ( y )

1

--------

3 x^3

(x^2y)/(3x^5y)

= [x^2/(3x^5)][y/y]

= [1/(3x^3)][1]

= 1/(3x^3)

i dunno, mabey 2X Y/15X Y?