The point P(1,8/7) lies on the graph of the function f defined by f(x)=8x/4+3x By Calculating the slope of the secant line PQ for the successive points Q (x, f(x)) with x=1.1 x=1.01 x=1.001 x=1.0001 and x=.9 x=.99 x=.999 x=.9999 estimate (to 3 decimal places) the slope of the tangent line to the graph of f at P
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I'm not going to do it for you, because it'll take more time than I want to spend. Basically, what you're going to do is sneak up on the slope of the curve by calculating the slopes of secants using points closer and closer together. You have to calculate the slope of the line joining
(1, 8/7) and (1.1, 8.8/7.1)
then calculate the slope of the line joining
(1, 8/7) and (1.01, 8.08/7.01)
the calculate the slope of the line joining
(1, 8/7) and (1.001, 8.008/7.001)
and so on. Note that the y-values I gave above are f(1.1), f(1.01), and f(1.001) respectively. Just use the standard slope formula.