Verified answer

I will assume that the two means "base two."

log2 x = 3-log2 2x

3 is equal to 3*log2 2 because the twos cancel out to make one. With logarithmic laws, we get:

log2 x =log2 2^3 - log2 2x

log2 x =log2 8 - log2 2x

With logarithmic laws, two logs with the same base subtracted equals a division problem:

log2 x = log2 8/2x

Same base, so what's inside is equal

x = 8/2x

2x^2 = 8

x^2 = 4

x = 2

x = 2

thats right