????? Thanks!
log(4x-5)-log(x-6)=1 or
log[(4x-5)/(x-6)] =1. If base of logarithm is b, then
[(4x-5)/(x-6)] = b or
4x -5 = bx - 6b or
(b-4)x = (6b -5) or
x = (6b-5)/(b-4) if b = 10 then x = 55/6
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log(4x-5)-log(x-6)=1 or
log[(4x-5)/(x-6)] =1. If base of logarithm is b, then
[(4x-5)/(x-6)] = b or
4x -5 = bx - 6b or
(b-4)x = (6b -5) or
x = (6b-5)/(b-4) if b = 10 then x = 55/6