x2 - 9
36y2 - 1
9a4 - b2
x10 - y2
i have to factor these...and idk if im right or wrong
All these questions r based on da factoring property: a² − b² = (a + b)(a − b)
x² − 9
= (x)² − (3)²
= (x + 3)(x − 3)
36y² − 1
= (6y)² − (1)²
= (6y + 1)(6y − 1)
9a⁴− b²
= (3a²)² − (b)²
= (3a² + b)(3a² − b)
x¹⁰ − y²
= (x⁵)² − (y)²
= (x⁵ − y)(x⁵ + y)
Hope this helps
Feel free 2 email me if u have any more questions !!
These are all the difference of two squares: A^2 - B^2 = (A + B)(A - B)
x^2 - 9 = x^2 - 3^2 = (x + 3)(x - 3)
36y^2 - 1 = (6y)^2 - (1)^2 = (6y + 1)(6y -1)
9a^4 - b^2 = (3a^2)^2 - b^2 = (3a^2 + b)(3a^2 - b)
x^10 - y^2 = (x^5)^2 - y^2 = (x^5 + y)(x^5 - y)
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Verified answer
All these questions r based on da factoring property: a² − b² = (a + b)(a − b)
x² − 9
= (x)² − (3)²
= (x + 3)(x − 3)
36y² − 1
= (6y)² − (1)²
= (6y + 1)(6y − 1)
9a⁴− b²
= (3a²)² − (b)²
= (3a² + b)(3a² − b)
x¹⁰ − y²
= (x⁵)² − (y)²
= (x⁵ − y)(x⁵ + y)
Hope this helps
Feel free 2 email me if u have any more questions !!
These are all the difference of two squares: A^2 - B^2 = (A + B)(A - B)
x^2 - 9 = x^2 - 3^2 = (x + 3)(x - 3)
36y^2 - 1 = (6y)^2 - (1)^2 = (6y + 1)(6y -1)
9a^4 - b^2 = (3a^2)^2 - b^2 = (3a^2 + b)(3a^2 - b)
x^10 - y^2 = (x^5)^2 - y^2 = (x^5 + y)(x^5 - y)