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A parachutist descending at a speed of 17.4 m/s loses a shoe at an altitude of 53.2m. What is the velocity of the shoe just before it hits the ground? The acceleration of gravity is 9.81 m/s^2.
When does the shoe reach the ground?
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we have to assume that the shoe will fall without experiencing friction
we can use the equation:
vf^2=v0^2+2ad
where vf=final velocity
v0=initial velocity = 17.4m/s
a=acceleration = 9.8m/s/s
d=distance traveled = 53.2m
in this case, acceleration is positive since the acceleration is in the same direction of the motion
vf^2=17.4^2 + 2*9.81*53.2
calculate and solve for vf