Verified answer

Fo the first question

Equation: y = kxz where k is a constant

96 = k(4)(8)

96 = 32k

32k = 96

k = 96/32

k = 3

Thus equation is now y = 3xz

When x = 1 and z = 4

y = 3(1)(4)

y = 12

For question 2

y = k / x

4 = k / 16

k = 64

y = 64 / x

When y = 8

8 = 64 / x

x = 64 / 8

x = 8

1) y=a xz

to find a

96=a*4*8

a=3

y=3xz

y=3*1*4=12

Equation: ___y=3 xz____

Solution: ___12____

2)y=k/x

to find k

4=k*16

k=1/4=0.25

y=0.25/x

solution

8=0.25/x

x=0.25/8=1/32=0.03125

Equation: __y=0.25/x______

Solution: ___0.03125_____