1)Consider a rectangular swimming pool of depth 1 m with a width and length of 19 m. What is the total force on the bottom of the pool due to the water pressure?
____N
2) A diver is swimming at a depth of 46 m. What is the pressure in the water around him?
______Pa
3)A swimming pool of depth 2.6 m is filled with ordinary (pure) water (ρ = 1000 kg/m3).
(a) What is the pressure at the bottom of the pool?
1.25E5 Pa
^^I got this right but don't know how to do the next st
(b) When the pool is filled with salt water, the pressure changes by 4.9E3 Pa. What is the difference between the density of the salt water and the density of pure water?
______kg/m3
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Answers & Comments
Verified answer
Pressure =( Density x Gravity acceleration x Height) + atmospheric pressure
1) 1000kg/m ^3 x 9.8m/s^2 x 1m = 9800 Pa ; 9.8E3 + 101.3E3 = 111.1E3 kPa
2) 9800 x 46 = 450 kPa + 101.3 kPa = 551.3 kPa
3) I get 1.27E5 close enough
4) Saltwater is more dense than fresh water, that's why we float more easily in saltwater. So the pressure change is added. For you answer 1.25E5 + 4.4E3 = 1.30E5 Pa ;
1.30E5 Pa - 1.013E5 = 2.87E4; density = 2.87E4/(9.8x2.6) = 1126 kg/m3 an increase of 126 kg/m3
Hope this helped
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